1.5: Experiment_605_Hydrates_1_2_1
- Page ID
- 303067
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Student Name |
Laboratory Date: Date Report Submitted: |
___________________________ |
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Student ID |
Experiment Number and Title |
Experiment 605: Hydrates |
Experiment 605: Hydrates
Section 1: Purpose and Summary
- Determine the percent water of hydration in a hydrate sample.
- Determine the number of moles of water, x, per mole of anhydrous salt and write the chemical formula of the hydrate sample.
Hydrates are ionic compounds that contain water molecules as part of their crystal structure. The bound water is called the water of hydration. Some compounds lose this water of hydration spontaneously (efflorescent) while some may require heating. On the other hand, an anhydrous salt (without water) can absorb water from the atmosphere and spontaneously dissolve in its own water of hydration (deliquescent).
A hydrate contains a definite number of water molecules bound to each ionic compound or anhydrous salt. In this experiment, students will dehydrate an unknown hydrate sample by heating, and calculate the amount of water lost in the process. Students will determine the ratio between the moles of water lost and the moles of anhydrous salt and write the chemical formula of the hydrate sample.
Section 2: Safety Precautions and Waste Disposal
Safety Precautions:
Use of eye protection is recommended for all experimental procedures.
A hot crucible will break if placed directly on a cold surface. Set hot crucibles on to wire screens to cool.
Waste Disposal:
When you are finished with the experiment, discard solid waste in the container marked ‘solid waste’ in the fume hood.
Section 3: Procedure
Part 1: Deliquescence and Efflorescence
Prepare two clean and dry watch glasses. Transfer a few crystals of sodium sulfate decahydrate, Na2SO4×10H2O, into one watch glass, and anhydrous calcium chloride, CaCl2, into the other. Observe each sample occasionally as you perform the rest of this experiment. Record your observations below. |
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Na2SO4×10H2O |
CaCl2 |
Part 2: Formula of an unknown hydrate
Possible unknowns: CaCl2×xH2O, CaSO4×xH2O, AlK(SO4)2×xH2O, MgSO4×xH2O
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Identification code for unknown: |
Allow the crucible to cool on the wire triangle. When the crucible is cool and safe to touch, weigh on an analytical balance. Record exact mass of the crucible and lid. |
Mass of crucible and lid:
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NOTE: You need to have both the total mass of the crucible, lid and sample as well as just the sample. You can determine the mass of the sample by subtraction of the mass of the crucible (a). |
Mass of crucible, lid and sample (before heating):
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Mass of crucible, lid and sample (after final heating):
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Mass of crucible, lid and sample (after 2nd, etc. final heating):
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Part 3: Reversibility of hydration
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Appearance of CuSO4.5H2O:
Appearance of solid after heating:
Appearance of the inside wall of the test tube after heating:
Appearance of solid residue after adding a few drops of laboratory water:
Section 4: Calculations
(b) – (a) |
Mass of the unknown hydrate sample: (e) _______________ grams |
(d) – (a) |
Mass of the heated sample (dehydrated): (f) _______________ grams |
(e) – (f) |
Mass of water lost: (g) _______________ grams |
% water= \(\frac{\text {mass of water lost (g)}}{\text { mass of hydrate (e)}}=\) x 100 |
Percent water in the hydrate: |
Identify of the anhydrous salt: ________________________ Molar mass of anhydrous salt: ___________________g/mol Show your equation here: |
Moles of anhydrous salt: (h) _______________ mol |
Molar mass of water, H2O: ___________________g/mol Show your equation here: |
Moles of water lost: (i) _______________ mol |
(i) ÷ (h) |
\(\frac{\text { mole of } H_{2} O}{\text { mole of anhydrous salt }}\) ratio (j) ____ : ____ |
For example, if a given amount of hydrated copper(II) sulfate gave off 0.060 mole of H2O and left behind 0.012 mole of anhydrous copper(II) sulfate, CuSO4, then the ratio of H2O to CuSO4 is 5:1, and the formula would be written as CuSO4×5H2O. |
Chemical formula of the unknown sample: |
Post-lab Questions
- Calculate the mass percent of water for the hydrate, LiNO3×3H2O.
- What will be the probable effect if you kept the crucible completely covered during the entire heating and cooling processes? Would your calculated percent water in the hydrate be high, low, or unaffected? Explain.
- If 2.752 g sample of Ca(NO3)2×xH2O is heated to constant mass, the residue weighs 1.941 g. Determine the value of x and the formula of the hydrate.
Notes: