# 11.7: The Combined Gas Law: Pressure, Volume, and Temperature

Learning Objectives

• Learn and apply the combined gas law.

One thing we notice about all the gas laws is that, collectively, volume and pressure are always in the numerator, and temperature is always in the denominator. This suggests that we can propose a gas law that combines pressure, volume, and temperature. This gas law is known as the combined gas law, and its mathematical form is

$\frac{P_{1}V_{1}}{T_{1}}=\dfrac{P_{2}V_{2}}{T_{2}}\; at\; constant\; n$

This allows us to follow changes in all three major properties of a gas. Again, the usual warnings apply about how to solve for an unknown algebraically (isolate it on one side of the equation in the numerator), units (they must be the same for the two similar variables of each type), and units of temperature must be in Kelvin.

Example $$\PageIndex{1}$$:

A sample of gas at an initial volume of 8.33 L, an initial pressure of 1.82 atm, and an initial temperature of 286 K simultaneously changes its temperature to 355 K and its volume to 5.72 L. What is the final pressure of the gas?

SOLUTION

Steps for Problem Solving

Identify the "given"information and what the problem is asking you to "find."

Given:

V1 = 8.33 L, P1 = 1.82 atm, and T1 = 286 K

V2 = 5.72 L and T2 = 355 K

Find: P2 = ? atm

List other known quantities

none

Plan the problem

First, rearrange the equation algebraically to solve for $$V_2$$.

$$P_2 = \frac{P_1 V_1 T_2 }{T_1V_2}$$

Calculate

Now substitute the known quantities into the equation and solve.

$P_2 = \frac{(1.82\, atm)(8.33\, \cancel{L})(355\, \cancel{K})}{(286\, \cancel{K})(5.72\, \cancel{L})}=3.22 atm$

Think about your result. Ultimately, the pressure increased, which would have been difficult to predict because two properties of the gas were changing.

Exercise $$\PageIndex{1}$$

If P1 = 662 torr, V1 = 46.7 mL, T1 = 266 K, P2 = 409 torr, and T2 = 371 K, what is V2?