10.31: Momentum-Space Variation Method for Particle in a Gravitational Field
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- 136980
The following problem deals with a particle of unit mass in a gravitational field with acceleration due to gravity equal to 1.
Energy operator for particles near Earth's surface:
\[ \frac{-1}{2 \mu} \frac{d^2}{dz^2} \blacksquare + z \blacksquare \nonumber \]
Trial wave function:
\[ \Psi ( \alpha , z) := 2 \alpha ^{ \frac{3}{2}} z exp(- \alpha z) \nonumber \]
Fourier the position wave function into momentum space:
\[ \Phi ( \alpha , p) := \frac{1}{ \sqrt{2 \pi}} \int_{0}^{ \infty} exp(-1 p z) \Psi ( \alpha , z) dz |_{simplify}^{assume,~ \alpha > 0} \rightarrow \frac{2 ^{ \frac{1}{2}}}{ \pi ^{ \frac{1}{2}}} \frac{ \alpha ^{ \frac{3}{2}}}{(ip + a)^2} \nonumber \]
Demonstrate that the momentum wave function is normalized.
\[ \int_{- \infty}^{ \infty} \overline{ \Phi ( \alpha , p)} \Phi ( \alpha , p) dp~~assume,~ \alpha > 0 \rightarrow 1 \nonumber \]
Energy operator in momentum space:
\[ \frac{p^2}{2} \blacksquare + i \frac{d}{dp} \blacksquare \nonumber \]
Evaluate the variational expression for the energy:
\[ E( \alpha ) := \int_{- \infty}^{ \infty} \overline{ \Phi ( \alpha , p)} \frac{p^2}{2} \Phi ( \alpha , p) dp ... + \int_{- \infty}^{ \infty} \overline{ \Phi ( \alpha , p)} i ( \frac{d}{dp} \Phi ( \alpha , p)) dp \nonumber \]
Minimize energy with respect to variational parameter \( \alpha\):
\( \alpha\) := 1 \( \alpha\) := Minimize (E, \( \alpha\) \( \alpha\) = 1.145 E( \(\alpha\)) = 1.966
This momentum space result is in exact agreement with the coordinate-space result. The exact value for the energy is 1.856.
\[ \frac{E ( \alpha) - 1.856}{1.856} = 5.9 \nonumber \]