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Chemistry LibreTexts

26.5: Units and Conversion Factors

  • Page ID
    192032
  • \[ \begin{array}{r c l} \hline 1 \text{ m} & = & 10^{–10} \text{ Å} \\ ~ & = & 3.280 840 \text{ ft} \\ ~ & = & 39.370 08 \text{ in} \\ \hline 1 \text{ kg} & = & 2.204 622 \text{ lb} \\ 1 \text{ lb} & = & 453.592 5 \text{ g} \\ \hline 1 \text{ m}^3 & = & 10^3 \text{ L} \\ ~ & = & 35.314 67 \text{ ft}^3 \\ ~ & = & 264.172 0 \text{ US liquid gallon} \\ \hline 1 \text{ N} & = & 1 \text{ kg m s}^{–2} \\ ~ & = & 1 \text{ Pa m}^2 \\ ~ & = & 10^{–5} \text{ bar m}^2 \\ ~ & = & 10^5 \text{dyne} ~ ( \text{g cm s}^{–2}) \\ ~ & = & 0.138 255 0 \text{ poundal} \\ \hline 1 \text{ bar} & = & 10^5 \text{ Pa} \\ ~ & = & 10^5 \text{N m}^{–2} \\ ~ & = & 0.986 92 \text{ atm} \\ ~ & = & 750.064 \text{ torr} \\ 1 \text{ atm} & = & 101 325 \text{ Pa} \\ ~ & = & 1.013 25 \text{ bar} \\ \hline 1 \text{ J} & = & 1 \text{ N m} \\ ~ & = & 1 \text{ Pa m}^3 \\ ~ & = & 1 \text{ W s} \\ ~ & = & 2 \text{ C V} \\ ~ & = & 10^7 \text{ erg} ~ ( \text{g cm}^2 \text{ s}^{–2}) \\ ~ & = & 10^{–5} \text{ bar m}^3 \\ ~ & = & 10^{–2} \text{ bar L} \\ ~ & = & 9.869 23 \times 10^{-3} \text{ L atm} \\ ~ & = & 0.239 0 \text{ cal} \\ 1 \text{ cal} & = & 4.184 \text{ J} \\ 1 \text{ eV} & = & 1.602 176 462 \times 10^{–19} \text{ J} \\ ~ & ~ & \begin{array}{l} \text{(Energy released when one electron} \\ \text{experiences a potential change of one volt.)} \end{array} \\ \hline \end{array} \nonumber\]

    Conversion factors in this table are given by, or calculated from, values given by David R. Lide, CRC Handbook of Chemistry and Physics, 79th Ed., CRC Press, 1999-2000, pp. 1-24 to 1-31, reproduced from NIST Special Publication 811, Guide for the Use of the International System of Units (Superintendent of Documents, U. S. Government Printing Office, 1991).

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