1.9: sp Hybrid Orbitals and the Structure of Acetylene
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- 448518
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In addition to forming single and double bonds by sharing two and four electrons, respectively, carbon can also form a triple bond by sharing six electrons. To account for the triple bond in a molecule such as acetylene, \(\mathrm{H}-\mathrm{C} \equiv \mathrm{C}-\mathrm{H}\), we need a third kind of hybrid orbital, an sp hybrid. Imagine that, instead of combining with two or three \(p\) orbitals, a carbon 2 s orbital hybridizes with only a single \(p\) orbital. Two \(s p\) hybrid orbitals result, and two \(p\) orbitals remain unchanged. The two \(s p\) orbitals are oriented \(180^{\circ}\) apart on the right-left \((x)\) axis, while the \(p\) orbitals are perpendicular on the up-down \((y)\) axis and the in-out \((z)\) axis, as shown in Figure \(\PageIndex{1}\).
When two sp-hybridized carbon atoms approach each other, sp hybrid orbitals on each carbon overlap head-on to form a strong sp–sp σ bond. At the same time, the pz orbitals from each carbon form a pz–pz \(\pi\) bond by sideways overlap, and the py orbitals overlap similarly to form a py–py \(\pi\) bond. The net effect is the sharing of six electrons and formation of a carbon–carbon triple bond. Each of the two remaining sp hybrid orbitals forms a σ bond with hydrogen to complete the acetylene molecule (Figure \(\PageIndex{2}\)).
As suggested by sp hybridization, acetylene is a linear molecule with H–C–C bond angles of 180°. The C–H bonds have a length of 106 pm and a strength of 558 kJ/mol (133 kcal/mol). The C–C bond length in acetylene is 120 pm, and its strength is about 965 kJ/mol (231 kcal/mol), making it the shortest and strongest of any carbon–carbon bond. A comparison of sp, sp2, and sp3 hybridization is given in Table \(\PageIndex{1}\).
| Molecule | Bond | Bond strength | Bond length (pm) | |
|---|---|---|---|---|
| (kJ/mol) | (kcal/mol) | |||
| Methane, \(\mathrm{CH}_4\) | \(\left(s p^3\right) \mathrm{C}-\mathrm{H}\) | 439 | 105 | 109 |
| Ethane, \(\mathrm{CH}_3 \mathrm{CH}_3\) | \(\left(s p^3\right) C-C\left(s p^3\right)\) | 377 | 90 | 153 |
| \(\left(s p^3\right) \mathrm{C}-\mathrm{H}\) | 421 | 101 | 109 | |
| Ethylene, \(\mathrm{H}_2 \mathrm{C}=\mathrm{CH}_2\) | \(\left(s p^2\right) \mathrm{C}=\mathrm{C}\left(s p^2\right)\) | 728 | 174 | 134 |
| \(\left(s p^2\right) \mathrm{C}-\mathrm{H}\) | 464 | 111 | 109 | |
| Acetylene, \(\mathrm{HC} \equiv \mathrm{CH}\) | \((s p) \mathrm{C} \equiv \mathrm{C}(s p)\) | 965 | 231 | 120 |
| \((s p) \mathrm{C}-\mathrm{H}\) | 558 | 133 | 106 | |
Draw a line-bond structure for propyne, CH3C≡CH. Indicate the hybridization of the orbitals on each carbon, and predict a value for each bond angle.
- Answer
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The CH3 carbon is sp3; the triple-bond carbons are sp; the C≡C−C and H−C≡C bond angles are approximately 180°.



