# 9.3: Single Covalent Bonds

In one form or another, the idea of atoms connecting to form larger substances has been with us for a long time. The Greek philosopher Democritus (460 - 370 BCE) believed that atoms had hooks on them that allowed atoms to connect with one another. Today we believe that atoms are held together by bonds formed when two atoms share a set of electrons, a much more complicated picture than the simple hooks that Democritus preferred.

## Single Covalent Bonds

A covalent bond form when two orbitals with one electron each overlap each other. For the hydrogen molecule, this can be shown as:

Upon formation of the $$\ce{H_2}$$ molecule, the shared electrons must have opposite spin, so they are shown with opposite spin in the atomic $$1s$$ orbital.

The halogens also form single covalent bonds in their diatomic molecules. An atom of any halogen, such as fluorine, has seven valence electrons. Its unpaired electron is located in the $$2p$$ orbital.

The single electrons in the third $$2p$$ orbital combine to form the covalent bond:

Figure 9.3.1: On the left is a fluorine atom with seven valence electrons. On the right is the $$\ce{F_2}$$ molecule.

The diatomic fluorine molecule $$\left( \ce{F_2} \right)$$ contains a single shared pair of electrons. Each $$\ce{F}$$ atom also has three pair of electrons that are not shared with the other atom. A lone pair is a pair of electrons in a Lewis electron-dot structure that is not shared between atoms. The oxygen atom in the water molecule shown below has two lone pair sets of electrons. Each $$\ce{F}$$ atom has three lone pairs. Combined with the two electrons in the covalent bond, each $$\ce{F}$$ atom follows the octet rule.

Example 9.3.1

Draw the Lewis electron dot structure for water.

Solution:

Step 1: List the known quantities and plan the problem

Known

• Molecular formula of water $$= \ce{H_2O}$$
• $$1 \: \ce{O}$$ atom $$= 6$$ valence electrons
• $$2 \: \ce{H}$$ atoms $$=2 \times 1 = 2$$ valence electrons
• Total number of valence electrons $$=8$$

Use the periodic table to determine the number of valence electrons for each atom and the total number of valence electrons. Arrange the atoms and distribute the electrons so that each atom follows the octet rule. The oxygen atom will have 8 electrons, while the hydrogen atoms will each have 2.

Step 2: Solve

Electron dot diagrams for each atom are:

$\ce{H} \cdot \: \: \: \: \: \cdot \underset{\cdot \cdot}{\overset{\cdot \cdot}{\ce{O}}} \cdot \: \: \: \: \: \ce{H} \cdot$

Each hydrogen atom with its single electron will form a covalent bond with the oxygen atom where it has a single electron. The resulting Lewis electron dot structure is:

$\ce{H} : \underset{\cdot \cdot}{\overset{\cdot \cdot}{\ce{O}}} : \ce{H}$