# 3.2: Exam 2

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1. (30 pts) A Rydberg transition promotes an electron to an orbital of a principal quantum number greater than that of any occupied orbital of the ground state. Consider the nd(n+1)s Rydberg excited state of a d2 ion. Construct the correlation diagram for the excited state in a D4h crystal field. For determining the ligand field states from the free ion states, you may use the equations given in the lecture notes and reproduced here (but it is not necessarily the only way to deduce the ligand field states):

\begin{gathered}
\chi(\alpha)=2 l+1 \quad \text { for } \alpha=0 \\
\chi(\alpha)=\frac{\sin (l+1 / 2) \alpha}{\sin \frac{\alpha}{2}} \quad \text { for } \alpha \neq 0
\end{gathered}

a. (5 pts) Which ligand will be stronger field, HC≡C- or OH-? Justify your choice.

b. (6 pts) Is the ground state of [CrCl6]3- subject to Jahn-Teller distortion? Explain why the 4T2g state (of (t2g)2 (eg)1 configuration) is subject to a Jahn-Teller distortion.

c. (4 pts) Under pressure, 10Dq of [CrCl6] 3- increases. Why?

d. (5 pts) In the lowest energy d-d excited state, [Ni(CN)4]2- undergoes a D4h → D2d distortion. Explain.

e. (10 pts) List the four states that arise from two electrons residing in two dxy orbitals in a D4h ligand field. The MO diagram with molecular orbital symmetries is given below. 3. (40 pts) The Co(sep)33+ is called a sephulcrate, first synthesized by Alan Sargeson at the Australian National University. Two absorption bands arising from spin-allowed ligand field transitions are observed for this complex. Assign these transitions by using the d6(Oh) Tanabe-Sugano diagram. Predict the energies of the corresponding spin-forbidden triplet transitions. 3.2: Exam 2 is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by Daniel Nocera via source content that was edited to conform to the style and standards of the LibreTexts platform; a detailed edit history is available upon request.