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7.7: Acid-Base Extraction

  • Page ID
    195204
  • An acid-base extraction is a type of liquid-liquid extraction. It typically involves different solubility levels in water and an organic solvent. The organic solvent may be any carbon-based liquid that does not dissolve very well in water; common ones are ether, ethyl acetate, or dichloromethane.

    Acid-base extraction is typically used to separate organic compounds from each other based on their acid-base properties. The method rests on the assumption that most organic compounds are more soluble in organic solvents than they are in water. However, if the organic compound is rendered ionic, it becomes more soluble in water than in the organic solvent.

    These compounds can easily be made into ions either by adding a proton (an H+ ion), making the compound into a positive ion, or by removing a proton, making the compound into a negative ion.

    Suppose you have a mixture of two compounds. There is a neutral one which does not react with any acids or bases. There is also a basic one, which reacts with acids by picking up a proton.

    In this case, a proton might be added via reaction with a strong mineral acid (represented by HX in the drawing). Suppose an aqueous solution of mineral acid, such as HCl, were shaken vigorously with an ethereal solution of an organic base and an organic neutral. The proton would be transferred to a basic compound, but not to a neutral one. The basic compound would become ionic, and more water-soluble.

    Note that in the drawing, the ether is represented in yellow, whereas the water is shown in blue. The water is on the bottom in this case because water has a higher density than ether, so it will sink to the bottom (along with anything dissolved in it). Some organic solvents do have a higher density than water, so the aqueous solution would float to the top in those case.

    clipboard_eb4938195d8177b98e726de07dd8f44be.png

    As a result, the ethereal solution would contain only the neutral compound, not the basic one. The neutral compound could be isolated simply by evaporating the ether.

    However, as a practical matter, the ether would have to be dried first. What's the difference between evaporating and drying? Have you ever been to the beach or taken a shower? Drying refers to the removal of water. This step is necessary because ether tends to dissolve a lot of water in it. Once the ether has been evaporated, there would be some neutral compound, but it would be mixed with water.

    Water removal is most easily done by adding a drying agent, such as magnesium sulfate or sodium sulfate. The water sticks to these solids, which are then filtered off.

    Now the neutral compound is alone in the ether. Evaporation of the ether gives the pure, neutral compound.

    However, the basic compound is stuck in the water, and it isn't the same compound anymore. It's an ion, now. If we want the original compound in a pure form, we need to take that proton away. That can be done by adding a mineral base, such as sodium hydroxide.

    clipboard_e2f038da53af3166b709675e9fa896a90.png

    The mineral base will remove the proton, leaving the original organic compound. The organic compound is uncharged and not as soluble in water anymore. It will go back into the ether layer.

    Conversely, we might have a mixture of an acidic organic compound and a neutral compound to start out with. In that case, we would add a mineral base in the first place, to take a proton away from the acidic compound. The mineral base might be something like sodium hydroxide or sodium bicarbonate. In the drawing, it is just represented as Na+ B-.

    clipboard_eb394235667fd502b8b680a89ccb9cb6d.png

    The acidic compound becomes ionic and water-soluble when it loses a proton. That leaves the neutral compound alone.

    To get that acidic compound back, we would add a mineral acid such as hydrochloric acid in order to restore the missing proton.

    clipboard_e3c0f17de2df11ce14da794c697e0fa23.png

    Just as in the other case, the ether layer containing a pure compound could be separated, dried and evaporated in order to provide the pure compound.

    But how do we know whether something is an organic acid or a base? Common structural features of organic acids and bases are displayed below.

    clipboard_e87d82bcc4af0e0bb60d7249e75a2bacd.png

    Note that the terms, "strong acid" and "weak acid", are relative. Sometimes, the term, "strong acid", designates a compound that completely ionizes in solution, so that it automatically gives up a H+ ion and forms an ionic compound. Hydrochloric acid, HCl, in water is a good example. That isn't true here; none of these acids ionize very easily on their own, and they appear in solution just as they do above, with just a small minority of molecules forming H+ and an anion. In this case, the term just compares one group of acidic compounds (called carboxylic acids) to another group of acidic compounds (called phenols). Carboxylic acids are more likely to give up protons than are phenols, so carboxylic acids are referred to in this context as "strong" and phenols as "weak".

    The carboxylic acid group contains a C=O (a carbonyl) with an additional OH group attached to the carbon. Examples are shown below.

    clipboard_ef2885e74f217d732accbe759a8ca1eaa.png

    When carboxylic acids are treated with mineral bases such as sodium hydroxide, the carboxylic OH group gives up a proton to the hydroxide, forming a water molecule. The electrons in the O-H bond stay behind, putting a negative charge on the resulting carboxylate anion. The salt that forms is much more water soluble.

    clipboard_ed4bc5e36c1d3b5c7766480d69e2b1342.png

    This reaction is completely reversible. A mineral acid, such as HCl, could provide protons to the carboxylate anion. The carboxylate ion would use a pair of electrons to bind to a proton, and the compound would become a neutral (as in uncharged) carboxylic acid again.

    Phenols also contain an OH group, but instead of being attached to a C=O group, the OH is attached to a benzene (a six-carbon ring with three double bonds). Examples are shown below.

    clipboard_ecc42cb7e8902d6162423fb40a9413840.png

    Phenols react with bases in the same way as do carboxylic acids. They just don't do so as easily.

    clipboard_e499f0ce3f9eca8535871d21636cb5f80.png

    Because phenols do not react as easily as carboxylic acids, there are situations in which a carboxylic acid would react with a base but a phenol would not. For example, carboxylic acids react even with weak bases such as sodium bicarbonate (baking soda).

    clipboard_efb90cf07747da92161dcec227029d2eb.png

    Phenols, on the other hand, do no such thing.

    clipboard_e845b14b15010b9555d898bc51522100a.png

    If the OH is attached to a carbon in an organic compound, but it is not attached to either a C=O or a benzene ring, it is not acidic enough to be removed to an appreciable extent. That is true even if there is a carbonyl or a benzene somewhere else in the molecule. As a result, acid-base extraction is not possible in these cases.

    clipboard_e82753070f71ace7b419c15b9defd2924.png


    Organic bases are compounds that contain nitrogen atoms. In order to be basic, the nitrogen atom must have a lone pair. The lone pair is needed in order to make a bond with the proton.

    clipboard_e184e7f9e245891afcbc09d95fd2e5f1a.png

    Once the lone pair has donated to the proton to form a bond with it, the nitrogen compound becomes positively charged. It then becomes more water-soluble.

    clipboard_ecd44f9d8eb9d8e377878ea3f66e5729b.png

    If the nitrogen does not have a lone pair, it is unable to bond to a proton. However, some compounds that do have a lone pair on the nitrogen still can't donate their lone pair to make a bond to the hydrogen. Most often that's because of a very electronegative oxygen atom nearby. The attraction of the oxygen for the lone pair makes the lone pair less able to donate to another atom. There can also be other reasons, especially involving electron delocalization or aromaticity that makes the lone pair unavailable for bonding.

    clipboard_e19b133a5d848af23d0c293e0ebaea5b1.png

    Exercise \(\PageIndex{1}\)

    If the following mixtures were taken up in ether and 1 M sodium hydroxide, indicate which compound would be found in each solvent.

    clipboard_e4ea34ea09c9f18a56622fc09d9496a8c.png

    Answer

    hydroxideextractsoln.png

    Exercise \(\PageIndex{2}\)

    If the following mixtures were taken up in ether and 1 M hydrochloric acid, indicate which compound would be found in each solvent.

    clipboard_e92c9921df1b3e452370d36e85663b140.png

    Answer

    hclextractsoln.png

    Exercise \(\PageIndex{3}\)

    If the following mixtures were taken up in ether and 1 M sodium bicarbonate, indicate which compound would be found in each solvent.

    clipboard_e71f1b28263f818951eebd757dbc98a6f.png
    Answer

    bicarbextractsoln.png

    Exercise \(\PageIndex{4}\)

    Indicate what compounds would be found in each solvent in the following cases.

    1. A mixture of cyclohexanone and octanoic acid is taken up in ether / 1 M sodium hydroxide.
    2. A mixture of benzylamine and dibenzyl ether is taken up in ether / 1 M hydrochloric acid.
    3. A mixture of propyl heptanoate and phenol is taken up in ether / 1 M sodium hydroxide.
    4. A mixture of 2-octanol and 3-bromobenzoic acid is taken up in ether / 1 M sodium hydroxide.
    5. A mixture of trioctylamine and heptanal is taken up in ether / 1 M hydrochloric acid.
    6. A mixture of 4-methoxyphenol and 3-nitrobenzoic acis is taken up in ether / 1 M sodium bicarbonate.
    Answer
    Answer a

    ether: cyclohexanone; water: sodium octanoate

    Answer b

    ether: dibenzyl ether; water: benzylammonium chloride

    Answer c

    ether: propyl heptanoate; water: sodium phenolate

    Answer d

    ether: 2-octanol; water: sodium bromobenzoate

    Answer e

    ether: heptanal; water: trioctylammonium chloride

    Answer f

    ether: 4-methoxyphenol; water: sodium 3-nitrobenzoate

    Exercise \(\PageIndex{5}\)

    Indicate what compounds would be found in each layer (top or bottom) in the following cases.

    1. A mixture of decanal and heptanoic acid is taken up in ethyl acetate / 1 M sodium hydroxide.
    2. A mixture of benzyl alcohol and 4-bromophenol is taken up in dichloromethane / 1 M sodium hydroxide.
    3. A mixture of 3-heptanone and N,N-dimethylbenzylamine is taken up in tert-butyl methl ether / 1 M hydrochloric acid.
    4. A mixture of benzoic acid and 2-methylhexanoic acid is taken up in chloroform / 1 M hydrochloric acid.
    5. A mixture of 2-ethylheptanoic acid and 4-chlorophenol is taken up in ether / 1 M sodium hydroxide.
    6. A mixture of benzonitrile and N,N-dimethyloctanamide is taken up in dichloromethane / 1 M hydrochloric acid
    Answer
    Answer a

    ethyl acetate (top): decanal; water (bottom): sodium benzoate

    Answer b

    dichloromethane (bottom): benzyl alcohol; water (top): sodium 4-bromophenolate

    Answer c

    ether (top): 3-heptanone; water (bottom): N,N-dimethylbenzylammonium chloride

    Answer d

    chloroform (bottom): benzoic acid, 2-methylhexanoic acid; water (top): nothing

    Answer e

    ether(top): nothing; water (bottom): sodium 2-ethylheptanoate, sodium 4-chlorophenolate

    Answer f

    dichloromethane (bottom): benzonitrile, N,N-dimethyloctanamide; water (top): nothing