5.6: Solutions for Selected Problems
- Page ID
- 190036
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Exercise 5.1.1:
a) 0 b) 3- c) 3- d) 3+ e) 5+
Exercise 5.1.2:
a) O2 b) NO2- c) 2 e-
Exercise 5.3.1:
- S: \(4 \times 2^{-} = 8^{-}\); Fe: \(2 \times 2^{+} + 2 \times 3^{+} = 10^{+}\); total \(= 2^{+}\)
- S: \(4 \times 2^{-} = 8^{-}\); Fe: \(1 \times 2^{+} + 2 \times 3^{+} = 8^{+}\); total \(= 0\)
- S: \(2 \times 2^{-} = 4^{-}\); Fe: \(2^{+} + 2^{+} = 5^{+}\); total \(=1^{+}\)
Exercise 5.3.2:
Exercise 5.3.3:
Exercise 5.3.4:
Exercise 5.4.1:
d) As the Fe becomes more reduced, the N-N stretching frequency decreases. That's because the more electron density there is on the Fe, the more it is able to backbond to the N2 (N2 is a π acceptor).